6t -20-32u6t−20−32u6, t, minus, 20, minus, 32, u when t=6t=6t, equals, 6 and u=\dfrac14u= 41 u, equals, start fraction, 1, divided by, 4, end fraction.
Accepted Solution
A:
The question is:Evaluate 6t−20−32u when t=6 and u=1/4Answer:8Step-by-step explanation:The given expression is:[tex]6t-20-32u[/tex]We need to evaluate the expression for the given values of t and u. Substituting t=6 and u=1/4 in the above expression we get:[tex]6(6)-20-32(\frac{1}{4} )\\\\ =36-20-8\\\\ =8[/tex]Thus, the give expression is equal to 8 for t=6 and u=1/4